Question

how do i solve sin^2(x)>=0 ?

Answer 1

so is it sin^(x)= 0?

Answer 2

(anything)^2 >= 0 unless its imaginary

Answer 3

prove \[\frac{\sin(2x)}{\sqrt{2-2\cos(2x)}}=\] and find any restrictions

Answer 4

prove it?

Answer 5

only resriction is 2-2cos(2x) > = 0

Answer 6

= sin(x) my bad

Answer 7

lol ok reask the question:)

Answer 8

can i copy paste equation ??