Question

Factor completely
4c^2+20ct+25t^2

Answer 1

can u think of 2 numbers with product 25*4=100
and sum = 20 ??

Answer 2

okay 5 and 4 is 20, 2 and 10, and 20 and 1; for a 100 i got 50 and 2, 1 and 100 and 25 and four

Answer 3

i want only 1 pair of numbers whose product is 100 and simultaneously those two number's sum is 20....

Answer 4

none of my numbers i've listed can be used for a pair

Answer 5

20

Answer 6

ok, u tried well, the numbers are 10 and 10 ok?

Answer 7

so now i will split the middle term 20ct as 10ct + 10ct , alright?
u now have
\(\huge 4c^2+10ct+10ct+25t^2\)
now can u take out 2c common from first two terms and tell me what u get??