Question

Did I do this right?

The question was to find the area of an isosceles triangle with 29 ft legs and a 40 ft base. I did this:

c^2=a^2+b^2
29^2=20^2+h^2
841=400+h^2
441=h^2
21=h

Area=1/2(base)(height)=1/2(40)(21)=420

I don't think I did it right...

Answer 1

looks ok...