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what is the standard form equation of a line passes through (5,-3) with a slope of -3
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y=mx+b where m is the slope and b is the y intercept
thus u can use y-y1 = m(x-x1) to get the line so... y - (-3) = -3(x - 5)
A/ 3x+y=12 B/3x+y=-12 C/3x-y=12 D/3x-y=-12
ahh lol
probably A the line of the equation is y = -3x+12
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thus 3x+y = 12
thanks
:)
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