Is 11101.111 (base2) EF in base 16?
hmmmmm 11101 = 2^0 + 0 + 4 + 8 + 16 = 29 in base 10 = 1D in base 16 - if my memory serves me right
i think he means 11101111
oh right
The problem is written as follows : 11101.111 and I am asked to write the following base 2 numbers in base 16.
to quickly change from base 2 to base 16, group 4 digits together 1 1101 . 1110 1 13 . 14 or using letters 1D.E
well, then its not EF for sure. to convert from base2 to base16 you can group binary digits by 4
I was confused to the decimal point. I didn't know why it was there.
1110 = E 1111 = F
So 100.1100101 would be 365?
it is a fractional number base 2 See http://www.wolframalpha.com/input/?i=11101.1110+base+2+to+base+16
it wud be 4.CA i think, you need to group by 4
I did group by 4.
110.1100101 is the correct base 2 number. I apologize I may have typed it in incorrectly.
100.1100101 would be 365? 0100 . 1100 1010 4 . C A
then 6.ca
HOW!
110.1100101 is same as 00000000000110.110010100000000000
it helps if you know your powers of 2 (memorized to 2^10 !) 8 4 2 1 0 1 1 0
the first digit of the fraction, from 1 1 0 0 is 8+4=12 or C 8 4 2 1
So 6CA?
you mean 6.ca with the "decimal" point
>_< I guess? I'm sorry guys I am terrible at math.
i must remember the groups of four thing
Why add leading zeros prior to the right most 1 in the problem?
not required, but it reminds you of what the 4th digit is.
It's the difference of if it's an A or not.
you dont have to if you dont wanto use the short cut. for using the short cut, you need four digits, so you need to add it
it is more important for the fractional end: 0.1 must be written as 0.1000 so you write 0.8 rather than 0.1 (base 16)
How can I get better at this stuff?
understand positional number system. once you grasp it you can do arithmetic in any numbersystem octal/binary/hexa... anything
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