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Mathematics 8 Online
OpenStudy (anonymous):

HELP

OpenStudy (anonymous):

OpenStudy (anonymous):

I started it and i got to 11+/-9 all over 2

OpenStudy (anonymous):

((x)/(x+3)) + ((3)/(x-1)) = ((13x - 1)/(X^2 +2x - 3)) ((x)/(x+3)) + ((3)/(x-1)) = ((13x - 1)/(X+3)(x-1)) (x-1)((x)/(x+3)) + (x-1)((3)/(x-1)) = (((13x - 1)/(X+3)) (x^2 - x) / (x + 3) + 3 = ((13x -1)/(x+3)) x^2 - x + 3x + 9 = 13x - 1 x^2 + 2x + 9 = 13x - 1 x^2 - 11x + 10 = 0 (x-10)(x -1) = x - 10 = 0 x = 10 and x -1 = 0 x = 1 x is 10 and 1

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