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I am supposed to factor completely. Help! 3b^3-5b^2+2b
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First factor out a b \[ b(3b ^{2} - 5b + 2)\] Does that makes sense? And do you know what to do from here?
Not really... haha would it be like factoring a trinomial?
Here let me show you how it can be done.\[3b ^{3} - 5b ^{2} + 2b\]\[b( 3b ^{2} - 5b + 2)\]\[b (3b - 1) (b + 2)\] That is how you factor it. If you multipled it all you will get the equation you started off with
The answer is actually. \[b (3b+1) (b-2)\]
Oh okay :D Thank you!
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