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How do I start solving this? x^3-3x^2-3x+9=0
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you can guess numbers that might work. they would have to divide 9, so your choices are \(\pm1,\pm3,\pm9\) although it need not be a rational number
it is very hard to solve a cubit equation in general, as the solutions need not be nice integers, they could be cube roots, square roots etc if i was going to do this i would cheat
*cubic
if you want a hint, try \(x=3\) then factor out \(x-3\) and then the other two will be easy to find
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