Question

Solve the inequality and write your answer in interval notation.
9x+16 greater than or equal to -9+6x

Answer 1

\[9x+16 \ge -9+6x\]
Combine like terms:
\[9x - 6x \ge -9-16\]
\[= 3x \ge -25\]
Divide by 3:
\[= x \ge -25/3\]
And now in interval notation:
\[x: [-25/3,\infty)\]