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Need help:2^(x+5) = 9 How do you get 2 and 9 to have the same bases? or how else could you do this problem?
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take natural log on both sides: ln(2^(x+5))=ln9
use the property: lna^b=b*lna, so you get: ln(2^(x+5))=(x+5)ln2=ln9
(x+5)=ln9/ln2 (x+5)=ln9/ln2
x=(ln9/ln2)-5
thank you :D
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do you know a good website that goes over natural logs and e well?
because I'm trying to do this next problem, and I don't know how to do it :(. This is the question: lnx+ln(x−6)=2
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