Question

f(x)=2x + 3x^2 + 5x^3 if x=5 then f(x)=710,
f '(x)=407, approximation=2035, how do we calculate the approximation

Answer 1

to calculate the average slope would be [f(a+h)-f(a-h)]/h where h is some small number (the smaller h the better the approximation)

Answer 2

2035 how to calculate it

Answer 3

so around x=5 you are calculating [f(5+h)-f(5-h)]/h where h is small
this is the equivalent to finding a secant line

Answer 4

what is that approximation of? the value of the function?

Answer 5

I don't know what they mean by "approximation" so I'm lost