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Mathematics 19 Online
OpenStudy (anonymous):

locate the absolute extrema of the function on the closed interval y= 3cosx, [0,2π]

OpenStudy (anonymous):

you know the plot Cosx?

OpenStudy (anonymous):

you know to plot Cosx?

OpenStudy (anonymous):

you know to plot Cosx?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

find the minimum and maximum of 3 cos x , [0,2π

OpenStudy (anonymous):

you know the maximum and minimum value of cos x for any x?

OpenStudy (anonymous):

|dw:1347439458875:dw|

OpenStudy (anonymous):

max is 1 min is -1

OpenStudy (anonymous):

how? please give the solution please. thank you :)

OpenStudy (anonymous):

the angle is varing between 0 to 2pi so if you plug in 0 then cos0 = 1 and you see the angle goes up to pi/2 then value of cosine is decreasing until it reaches x=pi

OpenStudy (anonymous):

so it is repeated in all angle...

OpenStudy (anonymous):

|dw:1347439734812:dw|

OpenStudy (anonymous):

i need the solution not the graph

OpenStudy (anonymous):

that is the solution...

OpenStudy (anonymous):

ok, thank you

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