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cscx=2 from 0 to pi how do find values of x??
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Invert both sides and sin(x)=1/2?
csc(x) = 1/sin(x) So: 1/sin(x) = y sin(x) = 1/y asin(sin(x)) = asin(1/y) = x
There will be two solutions: one in quadrant one and one in quadrant two.
Hmm, how do you find the second solution?
-(x+pi), no?
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Unit circle helps. |dw:1347469277124:dw|
x2=π-x1
(1/sin(x))=2 then solve for sin(x)=1/2 x=arcsin(1/2)
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