Question

@ is an operation that says a@b=a(b-a),if x-y=1,x+y=2,calculate (y@x)@y

Answer 1

then solve for x and y first
x=?
y=?

Answer 2

0

Answer 3

\[y(x-y)@y\]
\[y@y=(y-y)y\]=0

Answer 4

ya,did mentally, as u get y@y, u don't need to do anything else..