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log(base2) x - log(base2) (x-1) = 2
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\[\log_b(A)-\log_bC)=\log_b(A/C)\]
x/(x-1) = 4 where x is not 1 so x = 4x-4, x = 4/3
im not quite sure how you knew that x/(x-1) = 4 @LeeYeongKyu
|dw:1347517604968:dw|
oh i get it now thankyou
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