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[(7x+5)+4y][(7x+5)-4y]
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\[[a-b][a+b]=a^2-b^2\]
(a+b) (a-b)=a2-b2 then put 7x+5 in place of a and 4y in place of b.... then calculate and get the answer
That would only remove the grouping signs though, right?
yes but you will "have" to simplify it further also
So it is written like 7x+5+4y=7x+5^2-4y^2
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\[\large{(2x+5)^2-(4y)^2}\]
You have to simplify it further
\[\large{(7x+5)^2-(4y)^2}\] \[\large{(a+b)^2=a^2+2ab+b^2}\] \[\large{(7x+5)^2=? }\]
|dw:1347542928342:dw| this is the answer but u have to remember the formula that (a+b) (a-b)=a square - b square. this formula will help u in many other poblems
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