Question

A snail was chasing a worm. The worm (@ 2"/second) had a 75second head start. The snail was really full of caffeine and was really moving at 5"/seconf. how ling untill the snail reaches the worm?

Answer 1

@TuringTest @cshalvey @Bailey_Reona

Answer 2

long enough for the worm to get tired :)

Answer 3

rly @Bailey_Reona

Answer 4

lol yesh :D i win

Answer 5

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Answer 6

@TuringTest @cshalvey

Answer 7

I would answer your question but for that huge block of spam that is distracting me....

Answer 8

@TuringTest here then:

A snail was chasing a worm. The worm (@ 2"/second) had a 75second head start. The snail was really full of caffeine and was really moving at 5"/seconf. how ling untill the snail reaches the worm?

Answer 9

@TuringTest

Answer 10

@TuringTest

Answer 11

@TuringTest

Answer 12

let us call the distance traveled by the worm x(t)
let us call when the snail begins to move t=0
at t=0, how far has the worm moved?

Answer 13

idk

Answer 14

how long of a head start did he have?

Answer 15

75 seconds

Answer 16

and how fast was he moving for those 75 seconds?

Answer 17

2"/second so then it would be 75*2?

Answer 18

yes

Answer 19

so when the snail starts to move, (t=0) where is the worm? (x=?)

Answer 20

150 in?

Answer 21

yes, that is his initial position x(0)=150
now to find where he is at any given time, x(t), we add his initial position to how far he has traveled at any given time t
that is,
x(t)=x(0)+vt
where v is the velocity
plugging in the numbers for x(0) and v what does this formula become?

Answer 22

idk

Answer 23

what did we say x(0) was?

Answer 24

150

Answer 25

right, and what is his velocity?

Answer 26

2"/sec

Answer 27

so that is v (velocity times time is distance)
now plug those numbers fro x(0) and v into the formula
x(t)=x(0)+vt

Answer 28

where would 150 be??

Answer 29

and where would i put volacity?

Answer 30

x(0)=150
v=2

put those numbers in place of the letters in the equation

Answer 31

what would the t be in the +vt spot??

Answer 32

leave it as t, it is a variable and is what we are going to find
when we know the value of t that will be the time when the snail passes the worm, so for now we have to leave it as t

Answer 33

okay, then what?

Answer 34

write out the equation for x(t) with the numbers in and I'll tell you what to do next

Answer 35

x(t)=150+2t

Answer 36

good, that is the position function for the worm
now we need one for the snail, and we will find it the same way
what is the snails initial position x(0)?

Answer 37

5"/sec at 150??

Answer 38

@TuringTest

Answer 39

5 is the velocity of the snail, yes
but what is his initial position? why would it be 150 ? did he have a head start too?

Answer 40

my answer was better^.-

Answer 41

no it wasn't @Bailey_Reona. @TuringTest I don't know. is it 0??

Answer 42

YES! LOLL srry i couldn help

Answer 43

0.o you fail...

Answer 44

@cshalvey @hartnn

Answer 45

A snail was chasing a worm. The worm (@ 2"/second) had a 75second head start. The snail was really full of caffeine and was really moving at 5"/seconf. how ling untill the snail reaches the worm?

Answer 46

loll no not fail.

Answer 47

@ParthKohli @experimentX