Question

[(3x+y)+1]^2

Answer 1

using
\[(a+b)^2=a^2+2ab+b^2\]\[[(3x+y)+1][(3x+y)+1]\]
\[(3x+y)^2+2(3x+y)+1\]

Answer 2

what do I do after 6x^2+y^2+2

Answer 3

where do you get that

Answer 4

3x turns into 6x^2 right?

Answer 5

Nevermind... Would it be 6x^2+y^2+6x+2y+1

Answer 6

you have to open
\[(3x+y)^2+2(3x+y)+1\]

Answer 7

\[(3x+y)^2=9x^2+6xy+y^2\]

Answer 8

\[2(3x+y)=6x+2y\]
add them all up

Answer 9

is any of them going to be cubed

Answer 10

no,can you write me your final answer

Answer 11

there is no cube the highest degree is 2