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a car travelling at 7.0m/s acceleraes uniformly at 2.5 m/s square to reach a speed off 12.0 m/s. how long does it takes for this accelerataion to occur
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2.5 seconds.
Check it out... http://answers.yahoo.com/question/index?qid=20100831184805AAwWl2E
Soooo
\[\Large a={v-u \over t}\] u= initial velocity ... v= final velocity \[\Large \implies t= {v-u \over a}\]
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