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simplify and write expression with out a negative a^3b^2c^-2/ a^5b^2c^4=
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use this : \(\huge \frac{a^x}{a^y}=a^{x-y}\) so what would be \(\huge \frac{a^3}{a^5} \quad \frac{b^2}{b^2}\quad \frac{c^{-2}}{c^4}=?\)
|dw:1347551981942:dw|
nopes, \(\huge a^{(3-5)} b^{(2-2)} c^{(-2-4)} = ?\)
|dw:1347552119662:dw|
3-5 = ?
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-2
so it would be \(a^{-2}\) isn't it ? now since u want positive powers, u use \(\huge x^{(-y)}=\frac{1}{x^y}\)
so what would be \(\huge a^{-2}c^{-6}= ?\)
1/a^2c^6
yup , thats correct ....
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thanks again!
welcome again :)
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