Question

Find the equation of the perpendicular AND parallel line to each of the following that passes through the point indicated
-4/5x+y=-9 passing through the point (8,-3)

Answer 1

rewrite
y = (4/5) x - 9

the parallel line will have the same slope - that is 4/5
use the general equation
y-y1 = m(x-x1)
where m = slope 4/5 and (x1,y1) = (8,,-3)

Answer 2

can yu do these substitutions?

Answer 3

i need to find both parallel and perpendicular ,

Answer 4

and the equation is -4/5x-9

Answer 5

yes ok - the perpendicular slope is - 1 / m where m is the slope.
so in this case m = -1 / (4/5) = -5/4

so to find this equation substitute m = -5/4, x1 = 8 and y1 = -3
in the above equation

Answer 6

which is the correct equation - the one in the question or the one in your last post?

Answer 7

Last post.

Answer 8

i need the answers.

Answer 9

in that case the slope of the parallel line is -4/5 and of perpendicular line its -1 / (-4/5)
= 5/4.

Answer 10

parallel line:

y - (-3) = (-4/5)(x - 8)
which can be simplified

Answer 11

perpendicular line:

y - (-3) = (4/5)(x - 8)