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Determine real roots: (3x^2+27)(x^2-16) i don't understand how to solve this, please help ! :)
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What values for x make the expression equal to zero?
how do i figure that out ?
typos...
i know, but what i mean is that what method or technique is used here to figure it out
when (x^2-16) = 0 or (3*x^2+27) =0
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that's it really...solve for x
x^2=16 x=? x^2 =-9 x=?
glad I could help
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