Question

Point H(2,2) is the midpoint of many segments.
a segment with a midpoint H has a length of eight....
how many possible noncollinear segments would match that descriptionn?

Answer 1

There's an infinite number of segments. Since, if we picture a circle of radius four around point \(H\), then we have that every diameter is also a segment with the midpoint of \(H\), and none of these are co-linear.