Question

3-27x^3=0
is this solvable?

Answer 1

anything is solvable for a mathematician. they believe in imaginary things

Answer 2

Yep, it is:
\[
3-27x^3=0\implies\\
3=27x^3
\]Taking the third root of both sides:
\[
\sqrt[3]{3}=\sqrt[3]{27x^3}=3x\implies\\
x=\frac{\sqrt[3]{3}}{3}
\]This is for real \(x\).

Answer 3

thank you so much!

Answer 4

Sure thing!