Question

39+40+41+42+...+112

Answer 1

?

Answer 2

sum of arithmetic sequence huh

Answer 3

this is an arithmetic series with first term a= 39 , common difference d = 1 and last term an = 112
the sum of this series is given by
S=n/2(a+an)
can u find the sum now ?

Answer 4

use the formula \[\huge S_n = \frac{n(a_1 + a_n)}2\]
where:
n = number of terms
a1 = first term
a_n = last term

does that help?

Answer 5

to get n = number of terms,
u do last term - 1st term +1
so
n= 112 - 39 +1 = ?