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find the limit (if it exists). lim (1-[I -x/2l]) x->1
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\[\huge \lim_{x\rightarrow 1} (1 - [1 - \frac{x}{21}] )\] is that your question?
no i was trying to show the greatest integer symbol/sign
oh..that
yeah...
as \(x\) gets close to one, \(\frac{x}{2}\) gets close to \(\frac{1}{2}\) so greatest integer(\frac{x}{2} is 0 in an interval about 1
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i meant greatest integer of \(\frac{x}{2}\) is 0 in an interval about 1
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