Question

Picture of last two questions is now up pleaseeeeeee help :/ Numbers 35 and 36

Answer 1

for 35 a) 90<(m<Q)<180
thus u have to solve 90<2x-28<180
or 45<x-14<90
or adding 45 both sides we have 59<x<104

Answer 2

for 36 ) x^2-27x=90 or x^2 -27x-90=0 or x^2-30x+3x-90=0 or x(x-30)+3(x-30)=0 or (x-30)(x+3)=0 hence x=30 or -3

Answer 3

Thank You soooo much :)

Answer 4

welcome dear..