y = 13x^3 - 5x^2 + 6x - e^cos(10x)
y = 4x^3 + x^2 + 14x - e^cos(10x)

k so that last part since those r the same they cancel when finding the area between them? does this mean if it at the end of both they said (24x^5) that those would cancel to when finding the area between the 2 things?

Question

y = 13x^3 - 5x^2 + 6x - e^cos(10x) 
y = 4x^3 + x^2 + 14x - e^cos(10x)


k so that last part since those  r the same they cancel when finding the area between them?  does this mean if it at the end of both they said (24x^5) that those would cancel to when finding the area between the 2 things?

goten77 · Answer

im asking why do the e^(cos(10x)) cancel????

anonymous · Answer

No, but when you integrate the difference of the two functions to find the area betweeen the two, that e^(cos(10x)) part got cancelled.
see, ∫ (y1-y2 )dx
= ∫ 13x^3 - 5x^2 + 6x - e^cos(10x) -(  4x^3 + x^2 + 14x - e^cos(10x) dx
=∫( 9x^3 - 6x^2 -8x )dx

goten77 · Answer

oh i c y now XD