Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

please help me..how to solve this IxI-2=5??

OpenStudy (lgbasallote):

add 2 to both sides..what do you get?

OpenStudy (anonymous):

umm.... IxI=7

OpenStudy (lgbasallote):

right

OpenStudy (anonymous):

now??

OpenStudy (lgbasallote):

now...which number will give you 7 if you take the absolute value?

mathslover (mathslover):

- OR + ,,,,BOTH?

OpenStudy (anonymous):

sorry i didn't get you

OpenStudy (lgbasallote):

you're familiar what an absolute value is right?

OpenStudy (anonymous):

right

OpenStudy (lgbasallote):

| x | = a then x = a and x = -a

OpenStudy (anonymous):

so is it x=7

OpenStudy (lgbasallote):

right. what else?

OpenStudy (anonymous):

oh thank you got it :)

OpenStudy (lgbasallote):

welcome

hartnn (hartnn):

@lgbasallote , even @erica.d hates math !

OpenStudy (anonymous):

\[\left| x \right| = a gives x = +- a\]

OpenStudy (lgbasallote):

@hartnn who doesnt?

OpenStudy (anonymous):

thank you :)

hartnn (hartnn):

i don't.

OpenStudy (lgbasallote):

yeah @hartnn ...i don't know what happened to you

hartnn (hartnn):

??

OpenStudy (anonymous):

solve this \[^{}\left| x \right|-1=x2\]

OpenStudy (anonymous):

it is x square

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!