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simplify sqrt 12+ sqrt 16 + sqrt 8 - sqrt 2...help meee....
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\[\sqrt{12}=2\sqrt{3}\]
\[\sqrt{16}=4\]
\[\sqrt{8}=2\sqrt{2}\]
\[4+\sqrt{2}+2\sqrt{3}\]
\[2\sqrt{3}+4+2\sqrt{2}-\sqrt{2}\]
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did u understand how \(\sqrt {12} = 2 \sqrt 3\quad ??\)
yes...thank you guys and hartnn it's sqrt 2* sqrt2 *sqrt 3
yup, correct. u are smart :)
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