Question

solve:
2y^(1/2) + 0.2y

not sure how to..
trying 2.2*y^(3/2)
is that right??

Answer 1

\[2\sqrt{y}+0.2y=0\]???

Answer 2

I need to solve integral:
2pi*y*[(2rooty-(-0.2y)]dy

Answer 3

oh sorry :)

Answer 4

mhm

Answer 5

u have to solve \(\large \int2\pi y(2\sqrt y+0.2y)dy=\int 4piy^{3/2}dy+\int0.4\pi y^2dy \)
did u get this step ?
can u solve further ?

Answer 6

just take constants out of integral and use
\(\huge \int x^ndx=\frac{x^{n+1}}{n+1}+c\)

Answer 7

ive been doing that, getting it wrong

Answer 8

err i did a diff. problem and got it..was doing the #s on calculator wrong..ty

Answer 9

so u got the correct answer finally?

Answer 10

damn it im not getting it..

Answer 11

(8/5)pi y^(5/2) +(0.4/3)pi y^3
u getting this ?

Answer 12

damn it i was off by decimal points..b/c its the software on computer lol

Answer 13

i got it correct now..

Answer 14

great :)