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Verify that x-1 is a factor of x^(n) - 1
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if x-a is the factor of f(x) then f(a) = 0 now put x=1 in x^n-1 and see whether u get answer as 0.
put x=1 in above equation and if it reduces to zero then thats the factor
x^n - 1 = (x-1)(1 + x + x^2 +...+ x^n-1) Would you say that this is a good verification?
It just seemed too easy to me previously lol
yup, that verification will also do. just put there x=1 so (1-1)(....) = 0(...) = 0
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Got it! Thank you!
welcome :)
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