Question

Solve the absolute value equation and check:
|6x-4|-8=12

Answer 1

first add 8 to both sides, what u get ?

Answer 2

did u get
|6x-4| = 20 ??

Answer 3

Yes I got 20 but now I'm trying to figure out the other part...this is where I get confused.

Answer 4

ok, so if |a|=b
then a=b
OR a=-b
here
|6x-4| = 20
so
6x-4 = 20
OR
6x-4=-20
can u solve these 2 equations ??

Answer 5

hmm I'm still confused, math is not my subject ,I do much better with english ;) I'm thinking I need two solutions solving the absolute first...

Answer 6

yes, u will get 2 solution
one when solving for x in 6x-4 = 20
and other when solving for x in 6x-4 = -20
can u solve 6x-4 = 20 ??
hint :1st add 4 to both sides.

Answer 7

So I end up with -24/6 with x=4 for one, is this correct?

Answer 8

nopes, for
6x-4 = 20
u get
6x= 20+4= 24
x=24/6 = 4
ok ?

Answer 9

Ok and then how do I check the answer?

Answer 10

wait, 2nd equation is still remaining.
6x-4=-20
add 4
6x = -20+4
6x = -16
x= (-16/6) = -8/3
ok with this ?

Answer 11

please ask if u do not follow any step.

Answer 12

This equation I'm having a hard time understanding. so how did you get -16 and the -8/3?

Answer 13

oh I think I just figured it out except the -8/3 ;)

Answer 14

-20+4 =-16
ok, 20 -4 = 16 right ?
so -(20-4) = -16
-20+4 = -16
ok with this ?
and 16/6 = (8*2)/(3*2) = 8/3
2 getting cancelled from numerator and denominator.

Answer 15

ok so we just round up to the 3?

Answer 16

I get it now that I'm writing it down seeing the steps of how you ended up with each solution. Our instructor did not explain each step...it looks like a couple of the steps were skipped. I need to know each step since I'm not good at this. Thank you so much!

Answer 17

welcome :)
write and ask if there's still any doubts in any step...

Answer 18

still checking is remaining \(\checkmark \)
take one value which u got and put it again in left side of equation and see whether u get the right side.
so, lets take -8/3
so
|6x-4|-8
=|6(-8/3)-4|-8
=|-16-4|-8
=|-20|-8
=20-8 because |-a|=a
=12
so u get right side
so (-8/3) is \(\checkmark \)
can u do the same for x=4 now ??

Answer 19

@hills i assume u are trying.

Answer 20

lol Yes l'm just about done and then I will compare with yours. I was helping someone on another subject ;)

Answer 21

thats great :)

Answer 22

|6(4)-4|-8
=|24-4|-8
=|20|-8
=20-8
=12
so 4 is correct, right?

Answer 23

yes, u got it :)
\(\huge\checkmark\)

Answer 24

Yay! It sure helped following step by step ;) Again, thank you so much for your help!

Answer 25

welcome :)