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If you know of an arithmetic sequence X1 + X3 + X5 + X7 + X9 + X11 = 144, then X1 + X6 + X11 = . . .
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72 its simple.
6a+30d=144 so 3a+15d =72
X1 + X6 + X11 = 3a+15d
\[a+a+2d+a+4d+a+6d+a+8d+a+10d=144\]\[6a+30d=144\] \[3a+15d=\]
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