Question

A boy stands 39.2m from a buliding and throws a ball which just passes through a window 19.6m above the ground.Calculate the velocity of projection of the ball..

Answer 1

@ujjwal

Answer 2

@maheshmeghwal9

Answer 3

but wt is Sx?

Answer 4

Horizontal displacement o.O

Answer 5

no no no
wt is its value?

Answer 6

or we can do

Answer 7

IDK what imdoing lol

Answer 8

then how did u find Ux?

Answer 9

o.O

Answer 10

idk nvm

Answer 11

confused

Answer 12

isnt Sx=39.2m?

Answer 13

how?

Answer 14

A boy stands 39.2m from a buliding

Answer 15

oops my bad.
i misread the whole question:(

Answer 16

@Vaidehi09

Answer 17

yeah u r right.@DLS

Answer 18

@maheshmeghwal9 itsokay xD

Answer 19

:)

Answer 20

but what is theta

Answer 21

i think\[\theta \approx \tan^{-1}\frac{1}{2}\]

Answer 22

its 1

Answer 23

u got Vx and Vy ?

Answer 24

45degrees

Answer 25

Vx=19.6m/s
Vy=19.6m/s
Iguess

Answer 26

i m too confuseded:/

Answer 27

yup. thats it!

Answer 28

but..