Question

C++ question

Im learning to use functions. In this code, whenever I type in a full name, just the first name is displayed in the system. Any reason why?

Answer 1

/******************
***TEST C++ FILE***
*******************
*****Pradius******
******************/
#include <iostream>
#include <string>
using namespace std;

class Functions {
public:

void SetName(string x){
name = x;
}
string GetName(){
return name;
}
private:
string name;

};

int main()
{
string name;

Functions fobject;
cout << "What is your name\n";
cin >> name;
fobject.SetName(name);

cout << "Your name is " << fobject.GetName() << endl;
return 0;
}

Answer 2

bro .. i don't know c++..i know c and java.
so i think while inputing string as name , it takes the space as end of character and that's why it is not storing any character after space.
becoz in c , when we write scanf("%s",s); then it stores any characters before space.

Answer 3

mmm well that's not happen in Java... so how to solve it?

Answer 4

as i said.. i know c and java .. in c , you can use gets(str); in place of scanf()....

Answer 5

you can use getline(cin, yourstring);

Answer 6

What infinity said. When using stream operators in c++, it only reads up to the first whitespace.

Answer 7

#include <iostream>
#include <string>
using namespace std;

class Functions {
public:

void SetName(string x){
name = x;
}
string GetName(){
return name;
}
private:
string name;

};

int main()
{
string name;

Functions fobject;
cout << "What is your name\n";
getline(cin,name); //modification
fobject.SetName(name);

cout << "Your name is " << fobject.GetName() << endl;
return 0;
}