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Mathematics 15 Online
OpenStudy (anonymous):

what's the derivative of \[e^{-t}\]

OpenStudy (anonymous):

do u know the derivative for e^t ???

OpenStudy (anonymous):

yes its the same, e^t

OpenStudy (turingtest):

\[u=-t\]chain rule:\[\frac d{dt}f(u)=f'(u)\frac{du}{dt}\]

Parth (parthkohli):

Consider that\[{d \over d\text{number}}e^{\text{number}} = e^{\text{number}}\]

OpenStudy (anonymous):

use the formula |dw:1347723091039:dw|

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