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HippoCampus Algebra & Geometry
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OpenStudy (anonymous):
I need to know how to work: 2(x+4)^2=9
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OpenStudy (anonymous):
hm
OpenStudy (anonymous):
2(x+4)²=9, this is as similar as 2x²+16x+32=9, so, 2x²+16x +23=0. Now use Bhaskara´s equation and find the x´s values
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