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HippoCampus Algebra & Geometry 4 Online
OpenStudy (anonymous):

I need to know how to work: 2(x+4)^2=9

OpenStudy (anonymous):

hm

OpenStudy (anonymous):

2(x+4)²=9, this is as similar as 2x²+16x+32=9, so, 2x²+16x +23=0. Now use Bhaskara´s equation and find the x´s values

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