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silly question Why is x^2+4=0 x=+/-2i
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LOL
I remember now haha
\[x=\sqrt4\]
That's almost right.
Squaring i gets you -1, so 2i will be -1*(+/-2)^2
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negative sqrt which makes an imaginary number
thanks guys and gals
@across how it is almost right not right?
@pradipgr817, I don't understand your question. :P
@across I didn't got your comment "thats almost right"
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I said that because @MathSofiya wrote \(x=\sqrt4\) when it should have been \(x=\pm\sqrt{-4}\).
ok
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