Question

What is the end behavior of x^-4 as x approaches +/- infinity?
How does that negative exponent affect everything?

Answer 1

It's positive anyways.

Answer 2

As x approaches +infinity, y approaches + infinity as well I think
As x approaches -infinity, y approaches - infinity

Answer 3

the answer in the book says f(x) is 0 as x +/- infinity

Answer 4

x^-4 = 1/x^4
x-> ± ∞, since exponent of x is even
=> ( ± ∞ ) ^4 = ∞
Thus =1/∞ = 0

Answer 5

So, what do notice about negative exponent now?