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Grade 12 Polynomial Functions help please ~
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When 3x^2 + 10 x -3 is divided by x+ k , the remainder is 5. Determine values of k.
according to the remainder theorem u can write\[3x^2+10x-3=(x+k)Q(x)+r\]
u have r as 5
so\[3x^2+10x-3=(x+k)Q(x)+5\]now let x=-k and solve for k
\[3k^2-10k-3=(-k+k)Q(k)+5\]????
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