Question

x.y = 20
x.x.y.y = 328
x>y

how :
x.x.x-y.y.y ?
x.x.x.x+y.y.y.y.y ?

Answer 1

please , answer my question !!!!!!!!!!!!!

Answer 2

your question is wrong. are you sure you typed it correctly?

Answer 3

yes

Answer 4

when you say x.y = 20, you mean x times y =20 right?

Answer 5

is the second eqn what u have given is correct??

Answer 6

\[xy = 20\]\[y=\frac {20} x\]

\[x^2y^2 = 328\]\[x^2\left(\frac {20} x\right)^2=328\]\[20^2=328\]\[400=328???\]FALSE

Answer 7

xy=20 x=20/y

Answer 8

check your eqns.....

Answer 9

wrong question

Answer 10

there are no solutions to the first two equations