Question

If \(\Large{x+\frac{1}{x}=2}\),then \(\Large{x^2+\frac{1}{x^8}=?}\)

Answer 1

@mathslover @mukushla @sauravshakya plz help :)

Answer 2

solve the first equation for x

Answer 3

isn't it x^8 +1/x^8 ?

Answer 4

ok!\[x=2-1/x\]

Answer 5

\[x^2-2x+1=0\]