Question

A number, one-third of that number and one-forth of that number are added, the result is 38. what is the original nubmber?

Answer 1

n + n/3 + n/4 = 38
12n/12 + 4n/12 + 3n/12 = 38
19n/12 = 38
19n = 456
n = 456/19 = 24

Answer 2

Classical algebra question. Start by calling the number \(x\). Then we can set up the equation:
\[x+\frac{x}{3}+\frac{x}{4}=38\]
If we multiply by 12 (to get rid of the fractions) we will get:
\[12x+4x+3x=456\]
Collecting the x terms:
\[19x=456\]
\[x=24\]