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Mathematics 6 Online
OpenStudy (anonymous):

(a+b-c)(a+b+c)(a-b-c)(a-b+c) = ?

OpenStudy (anonymous):

simplify it?

OpenStudy (anonymous):

\[ (a+b-c)(a+b+c)(a-b-c)(a-b+c)\]\[ (a-b-c)(a+b+c)(a-(b-c))(a+(b-c))\]\[(a^2-(b+c)^2)(a^2-(b-c)^2)\]

OpenStudy (theviper):

yep

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