Question

If f' is continuous on[0,1] such that f(0) = 3 and f(1)=-1 then
\[\int\limits_{0}^{1}f'(x)\sqrt{1+f(x)}\].dx =?

Answer 1

have u tried u-sub?

Answer 2

let\[u=1+f(x)\]see what happens

Answer 3

thanks

Answer 4

np :)