Question

the greatest height to which a man can throw a stone is h,What will be the greatest distance upto which he can throw

Answer 1

\[ v=sqrt{2gh}\], the max. speed he can throw it..so apply the projectile equation and the max. distanc is 2h...at an angle of 45 degree..

Answer 2

the max. distance is 2h..try H.C Verma..is a great book..

Answer 3

how did you get 2h?

Answer 4

can u find the max. velocity with which he can throw?

Answer 5

u^2/2g = h
u^2/g=R
i got thismuch

Answer 6

then put the value of u^2...we get the answer