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Mathematics 20 Online
OpenStudy (anonymous):

Factor 3x^2+4x-132=0

OpenStudy (anonymous):

I'd just use the quadratic for that, you'll save time rather than staring at 132 for an hour wondering what its factors may be (unless you're good at factoring...)

OpenStudy (anonymous):

I had to use the quadratic but the answer would be (3x+22)(x-6)

OpenStudy (cwrw238):

it helps to factor 3 and 132 3* 1 - 2 * 2*3*11* 1 yes 3 * -6 and 1 * 22 are the required numbers to get -132 and + 4

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