Question

Someone please help:
Integral help.

Integrate: sinx/x^2 dx

Answer 1

integration by parts

Answer 2

Integrate by parts twice,\[\int\limits \frac{dv}{dx}udx=uv-\int\limits v\frac{du}{dx}dx\]Treat sinx as v both times, as the sign will reverse and you can cancel.

Answer 3

is the answer -sinx/x ?