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4-3x/2 > x-2/3 I got 32/19 and 7/4... but the answer key says x <16/11
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is this \(4-\frac{3}{2}x>x-\frac{3}{2}\) ?
2 covers the whole equation on the left side and 3 on the right side
ok let me try again
\[\frac{4-3x}{2}>\frac{x-2}{3}\]
correct
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multiply both sides by 6 get \[3(4-3x)>2(x-2)\] then \[12-9x>2x-4\]
add \(9x\) get \[12>11-4\]add 4 get \[16>11x\]divide by 11 gives your answer
sorry i meant add \(9x\) get \(12>11x-4\)
in multiplying by 6. How did you get the 3 on the left side and 2 on the right side?
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